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MoRe HeLp PlEaSe!! (calc)
Also can I get some help with this LONG, TIRESOME PROBLEM? Find the derivative using the chain rule. f(x)= ((3x7)/(6x+3))^4 Thanks a lot! (68/(12x^2+12x+3))*[(3x7)/(6x+3)]^3 you should double check the answer multiply
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Please help with this very complicated question! Using 3(x3)(x^26x+23)^1/2, as the chain rule fifferentiation of f(x)=(x^26x+23). Please explain how I find the general solution to dy/dx= 2/27(x3)SQUARE ROOT BEGINS
asked by Amy on April 18, 2011 
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Any help would be much appreciated with the steps involved in each problem given. Thank you. 1) Find derivative if y =cot x + sin x 2) Find derivative if y = (3x+5)^8 3) Find derivative if y = x csc x 4) Find derivative if y = x
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Any help would be much appreciated with the steps involved in each problem given. Thank you. 1) Find derivative if y =cot x + sin x 2) Find derivative if y = (3x+5)^8 3) Find derivative if y = x csc x 4) Find derivative if y = x
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In addition, can you walk me through how to get the derivatives for these 2 statements, too? a) y = x^5/3  5x^2/3 b) y = (the cubed root of the quantity) [(x^2  1)^2] Hi there. I need to find the first derivative of this
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Any help would be much appreciated with the steps involved in each problem given. Thank you. 1) Find derivative if y =cot x + sin x 2) Find derivative if y = (3x+5)^8 3) Find derivative if y = x csc x 4) Find derivative if y = x
asked by Matt on September 30, 2007 
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I posted this below, and no one answered. Please help with this very complicated question! Using 3(x3)(x^26x+23)^1/2, as the chain rule differentiation of f(x)=(x^26x+23). Please explain how I find the general solution to the
asked by Amy on April 19, 2011 
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I posted this below, and no one answered. Please help with this very complicated question! Using 3(x3)(x^26x+23)^1/2, as the chain rule differentiation of f(x)=(x^26x+23). Please explain how I find the general solution to the
asked by Amy on April 21, 2011 
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Find the derivative of the function. y= xcosx  sinx What's the derivative? I get only one trig function. I will be happy to critique your work or thinking. Use the chain rule on the first term. Our class hasn't covered Chain
asked by Jonah on March 6, 2007 
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Using 3(x3)(x^26x+23)^1/2, as the chain rule differentiation of f(x)=(x^26x+23). Please explain how I find the general solution to the differential equation dy/dx= 2/27(x3)SQUARE ROOT BEGINS (x^26x+23)/y SQUARE ROOT ENDS
asked by Tony on May 12, 2011