algebra

Use the given zero to find the remaining zeros of the function.
(hx)= 3x^4+5x^3+25x^2+45x-18; zero:-3i






labe

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asked by mary
  1. complex roots always come in conjugate pairs, so we have
    x = -3i and x = 3i
    two factors are (x + 3i) and (x- 3i)
    (x+3i)(x-3i)
    = x^2 - 9i^2 = x^2 + 9

    Using long algebraic division, you should get
    ( 3x^4+5x^3+25x^2+45x-18) ÷ (x^2+9)
    = 3x^2 + 5x + 2

    the quadratic formula can be used to find the other two roots.
    btw, it factors

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    posted by Reiny

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