The first term of an A.P is 2 and the common difference is 3. Find the sum of the first 11 terms
geez - just plug your numbers into the formula:
S11 = 11/2 (2*2+10*3)
My question do not answered
To find the sum of the first 11 terms of an arithmetic progression (A.P.), we can use the formula:
Sum(n) = (n/2)(2a + (n-1)d)
where:
- Sum(n) is the sum of the first 'n' terms of the A.P.
- 'a' is the first term of the A.P.
- 'd' is the common difference of the A.P.
- 'n' is the number of terms we want to sum.
In this case, we are given that the first term 'a' is 2 and the common difference 'd' is 3. We want to find the sum of the first 11 terms, so 'n' equals 11.
Let's substitute these values into the formula:
Sum(11) = (11/2)(2(2) + (11-1)(3))
Simplifying further:
Sum(11) = (11/2)(4 + 10(3))
= (11/2)(4 + 30)
= (11/2)(34)
= 11 * 17
= 187
Therefore, the sum of the first 11 terms of the given A.P. is 187.