# physics

A brick is thrown upward from the top of a building at an angle of 35° to the horizontal and with an initial speed of 15 m/s. If the brick is in flight for 2.7 s, how tall is the building? (in m)

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1. We just need to do the vertical part of the problem. I assume it hit the ground where H = 0

Vi = 15 sin 35 = 8.6 m/s up

H = Hi + Vi t - 4.9 t^2

0 = Hi + 8.6 (2.7) - 4.9 (2.7)^2

Hi = 12.5 meters

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posted by Damon

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