I am so lost and confused right now with this question. I might have a quiz. Help me understand before this pop quiz!!!! THANKYOU
A diver runs horizontally with a speed of 1.2 m/s off a platform that is 10.0 meters above the water.
a) how long before the diver hits the water?
b.) at what horizontal position from the end of the diving board does he hit the water?
c.) what is the diver's velocity just before hitting the water?
do vertical and horizontal problems separately
Vertical
Just plain fall, no initial velocity up or down
so a)
10 = (1/2)(9.81) t^2
b)
use that t to find out how far away he landed
d = u t = 1.2 t
c)
vertical v = g t = 9.81 t
horizontal u = 1.2
speed = sqrt (u^2+v^2)
direction
tan angle below horizontal = |v|/u
No problem! I'll help you understand how to solve each part of the question.
a) To find out how long it takes for the diver to hit the water, we can use the formula:
time = distance / velocity
In this case, the distance is the height of the platform, which is 10.0 meters, and the velocity is the horizontal speed of the diver, which is 1.2 m/s. So, we have:
time = 10.0 m / 1.2 m/s
By dividing 10.0 meters by 1.2 meters per second, you'll get the time it takes for the diver to hit the water.
b) To determine the horizontal position from the end of the diving board where the diver hits the water, we can use the formula:
distance = velocity * time
We already have the time calculated from the previous step. Now we need to find the horizontal distance traveled by the diver. The velocity is still 1.2 m/s, and the time is the value we found in part (a). Plug the values into the formula to get the horizontal distance.
c) To determine the diver's velocity just before hitting the water, we can use the concept of conservation of energy. Since no external forces act on the horizontal motion of the diver, the horizontal velocity remains constant. Therefore, the diver's velocity just before hitting the water will be the same as the horizontal velocity, which is 1.2 m/s.
By following these steps, you should be able to find the answers to all three parts of the question.