physics

a uniform beam 6.0 metre long and weighing 4kg rests on support at p and q placed left and right 1.0 metres from each end of the beam weights of mass 10 kg and 8kg are placed near p and q respectively one each end of the beam.calculate the reaction at p and q?

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  1. p and q are 4.0 m apart

    moments around q
    4 p = (10 * 5) + (4 * 2) - (8 * 1)
    p = 12.5
    Rp = 12.5 g

    moments around p
    4 q = (8 * 5) * (4 * 2) - (10 * 1)
    q = 9.5
    Rq = 9.5 g

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  2. clarifying

    Rp = 12.5 * g

    Rq = 9.5 * g

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  3. I don't know that why am asking you

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  4. i need more clarity on why it had to be done that way

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  5. I dont understand the calculation

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  6. i doot understand the calculation

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  7. Correct

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  8. am not getting the sense

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  9. i dont understand the solutions

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  10. I want to learn physics very well

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  11. Pls if possible can you snap and post
    the diagram for clarity

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  12. Correct

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  13. Tnks

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  14. After sketching the diagram.
    P+Q=220 N (Newton)
    Taking moment about point P
    40*2 + 80*5 = 4Q +100*1
    80 + 400 = 4Q + 100
    480 - 100 = 4Q
    380 = 4Q
    Q = 380/4
    Q = 95 N
    P + Q = 220 N
    P +95 = 220
    P = 220 - 95 = 125 N
    P =125 N

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