calculus 2

Sketch the region enclosed by the given curves. Find its area.
y=7cos pi x, y=12x^2-3

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1. See

http://www.wolframalpha.com/input/?i=plot+y%3Dcos%28pi*x%29%2C+y%3D12x^2-3

the curves intersect at (-1/2,0) and (1/2,0).

So, it's just a straightforward integral. Since things are symmetric, the area is just

2∫[0,1/2] cos(πx)-(12x^2-3) dx

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posted by Steve

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