how do i find dy/dx of
y = (x^3-1)/cos(x)
do I start with (x^3-1)*cos(x)^-1 ?
Thanks!
I would use the quotient rule
y' = [(cosx)(3x^2) - (-sinx)(x^3 - 1)]/(cos2 x)
= ....
y = (x^3-1)/cos(x)
do I start with (x^3-1)*cos(x)^-1 ?
Thanks!
y' = [(cosx)(3x^2) - (-sinx)(x^3 - 1)]/(cos2 x)
= ....