# Maths

Find the equation of a circle which diameter has the end point A (5, 4), B (7,4 ).

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1. the midpoint of the diameter is the center of the circle: (6,4)

The radius is half the diameter: 1

(x-6)^2 + (y-4)^2 = 1

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posted by Steve
2. Correct steve

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X^2 + y^2 - r^2 - 12x - 8y + 52 = 0

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X^2 + y^2 - r^2 - 12x - 8y + 52 = 0

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5. My money is on Steve's correct answer.

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posted by Reiny
6. Steve got it but it did nt reach quarter of d workings

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posted by Afeez

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