calculus 2

Use a graph to find approximate x-coordinates of the points of intersection of the given curves. Then find (approximately) the area of the region bounded by the curves. (Round your answer to two decimal places.)
y = 8x^2− 3x, y = x^3−8x+ 2

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  1. for some nice graphing, with scalable axes, go to

    Type in your functions (up to 3 of them). (Type them in, if you copy and paste from the post, the minus sign is really a dash, which the web site does not interpret.)

    Set the x range from -3 to 3
    Set the y range from -1 to 9

    Now you read off the approximate coordinates.

    The area is just the integral between those two x-values of the top curve minus the bottom curve.

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  2. I got 2812.76 for the answer but it said that's wrong

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  3. never mind I figured it out. The correct answer is 498.76

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