# chemistry

The titration of 5.40 mL of a saturated solution of sodium oxalate, Na2C2O4, at 25∘C requires 29.4 mL of 2.200×10−2 M KMnO4 in acidic solution.

What mass of Na2C2O4 in grams would be present in 1.00L of this saturated solution?

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1. You can balance the entire equation if you wish but the only part that matter is the redox part. Here is that part.
5C2O4^2- + 2MnO4^-==>2Mn^2+ + 10CO2

mols KMnO4 = M x L = ?
Using the coefficients in the balanced equation, convert mols KMnO4 to molsl Na2C2O4.
Then grams Na2C2O4 = mols Na2C2O4 x molar mass Na2C2O4 and that is grams in a 5.40 mL sample of the Na2C2O4. Convert to grams in 1 L.

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