What is the mass of water (in grams and pounds). contained in a 100. foot long pipe that has an internal diameter of 6.5 centimeters? The density of water is 1.00 g/ cm^3. The volume of a cylinder is (pi)r^2L.
mass = volume * density
v = pi (6.5cm/2)^2 (100ft * 30.48cm/ft) = 101142 cm^3
you have the formulas and the numbers -- what's the problem?
r = 6.5/2
Where did you get the 2 to divide by?
and what about the 30.48? Not sure of how to set this problem up. 6.5/2= 3.25 and I do not see that in the problem?
To find the mass of water in the pipe, we need to calculate the volume of water first, using the formula:
Volume = (pi) * (radius^2) * height
Given that the internal diameter of the pipe is 6.5 centimeters, we can calculate the radius by dividing it by 2:
Radius = Diameter / 2 = 6.5 cm / 2 = 3.25 cm
Next, we need to convert the height from feet to centimeters. Given that 1 foot is equal to 30.48 centimeters, the length of the pipe in centimeters is:
Length = 100 ft * 30.48 cm/ft = 3048 cm
Now we have all the necessary values to calculate the volume:
Volume = (pi) * (3.25 cm)^2 * 3048 cm
Simplifying this expression, we get:
Volume ≈ 314.16 * 10.5625 * 3048 cm^3 ≈ 10,196,499.02 cm^3
Since the density of water is given as 1.00 g/cm^3, we can multiply the volume by the density to obtain the mass:
Mass = 10,196,499.02 cm^3 * 1.00 g/cm^3
Finally, the mass of water in grams is approximately 10,196,499.02 grams.
To convert this mass to pounds, we need to know that 1 pound is equal to approximately 453.592 grams. Thus, we can calculate:
Mass in pounds ≈ 10,196,499.02 g / 453.592 g/pound
The mass of water in pounds is approximately 22,481.48 pounds.