find the standard form of the equation of the line that satisfies the given condition.
x-intercept: -4
y-intercept: 2
y=-4x+2
Jessica's answer is not correct.
x intercept point = -4,0
y intercept point = 0,2
y = mx + b is the standard line equation
where:
m = the slope of the line
b = the y intercept
The problems gives the y intercept as 2.
slope = (delta y)/(delta x)
= (0 - 2)/(-4 - 0)
= -2/(-4)
=?
To find the standard form of the equation of a line given the x-intercept and y-intercept, you can use the intercept form of a linear equation, which is given by:
x/a + y/b = 1
where a is the x-intercept and b is the y-intercept.
In this case, the x-intercept is -4 and the y-intercept is 2. So, we substitute these values into the intercept form equation:
x/(-4) + y/2 = 1
To convert this equation to standard form, we need to eliminate the fractions. We can do this by multiplying every term by the least common multiple (LCM) of the denominators, which is 2 * (-4) = -8:
-8(x/(-4)) + (-8)(y/2) = (-8)(1)
This simplifies to:
2x - 4y = -8
So, the standard form of the equation of the line that satisfies the given condition is 2x - 4y = -8.