Algebra

were suppose to see if its a function or not and i don't get these problems can you explain it to me?

1) X=15

2) y=3x+2y

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asked by James
  1. If there is one and only one value for the dependent variable in the domain then it is a function.
    x = 15 is not a function because there are an infinite number of y values along the vertical line x = 15
    however y = 3x+2y (I assume not a typo with that second y) is
    y = -3x
    which is a straight line with one value of y for every x. Therefore y is a function of x

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    posted by Damon
  2. if i were to graph it (question2)would it be on the negative side or positive side

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    posted by James
  3. Both James. That line goes from the upper left to the lower right, passing through (0,0)

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    posted by Damon
  4. yes but i still don't get how you got that (1st james)whats the coordinates

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    posted by James
  5. Well you wrote
    y = 3x+2y
    (I still wonder if it is not a typo, check the book to see if that second y term should really be just 2 and not 2y)
    I subtracted y from both sides to get
    0 = 3 x + y
    then subtracted 3x from both sides to get
    y = -3x
    Now that is a straight line through the origin with a slope of -3

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    posted by Damon
  6. try several values o x
    like
    x = - 1, then y = -3*-1 = 3
    x = 0, then y = -3*0 = 0
    x = +1, then y = -3*1 = -3

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    posted by Damon
  7. (1st james) that means to make a parabola with a slope of -3

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    posted by James
  8. It is a line. There is no x^2 in it so it is not a parabola.
    It is of form
    y = m x + b, a line
    where m, the slope is -3 and b is zero.

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    posted by Damon

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