# Algebra

were suppose to see if its a function or not and i don't get these problems can you explain it to me?

1) X=15

2) y=3x+2y

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1. If there is one and only one value for the dependent variable in the domain then it is a function.
x = 15 is not a function because there are an infinite number of y values along the vertical line x = 15
however y = 3x+2y (I assume not a typo with that second y) is
y = -3x
which is a straight line with one value of y for every x. Therefore y is a function of x

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posted by Damon
2. if i were to graph it (question2)would it be on the negative side or positive side

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posted by James
3. Both James. That line goes from the upper left to the lower right, passing through (0,0)

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posted by Damon
4. yes but i still don't get how you got that (1st james)whats the coordinates

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posted by James
5. Well you wrote
y = 3x+2y
(I still wonder if it is not a typo, check the book to see if that second y term should really be just 2 and not 2y)
I subtracted y from both sides to get
0 = 3 x + y
then subtracted 3x from both sides to get
y = -3x
Now that is a straight line through the origin with a slope of -3

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posted by Damon
6. try several values o x
like
x = - 1, then y = -3*-1 = 3
x = 0, then y = -3*0 = 0
x = +1, then y = -3*1 = -3

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posted by Damon
7. (1st james) that means to make a parabola with a slope of -3

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posted by James
8. It is a line. There is no x^2 in it so it is not a parabola.
It is of form
y = m x + b, a line
where m, the slope is -3 and b is zero.

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posted by Damon

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