55 gm laughng gas contains ---------gm N.
To determine the amount of nitrogen (N) present in 55 grams of laughing gas, we need to know the molecular composition of the compound. Laughing gas, or nitrous oxide (N2O), consists of two nitrogen atoms and one oxygen atom.
The atomic mass of nitrogen (N) is approximately 14.01 grams per mole. Therefore, the molecular mass of nitrous oxide (N2O) can be calculated as follows:
Molecular mass of N2O = (2 x atomic mass of N) + atomic mass of O
= (2 x 14.01) + 16.00
= 28.02 + 16.00
= 44.02 grams per mole
Now, we can use this information to find the amount of nitrogen present in 55 grams of laughing gas.
Number of moles of N2O = Mass of N2O / Molecular mass of N2O
= 55 grams / 44.02 grams per mole
≈ 1.25 moles
Since there are two nitrogen atoms in one mole of nitrous oxide (N2O), the total amount of nitrogen can be calculated as:
Amount of N = Number of moles of N2O x (2 moles of N / 1 mole of N2O)
= 1.25 moles x (2/1)
= 2.5 moles
Finally, to convert moles of nitrogen (N) to grams, we use the atomic mass of nitrogen:
Mass of N = Amount of N x Atomic mass of N
= 2.5 moles x 14.01 grams per mole
= 35.025 grams
Therefore, 55 grams of laughing gas contains approximately 35.025 grams of nitrogen (N).