A man spends 15% of his money and after spending 60% of the remainder he has 4080. Find the money he had at beginning?
after the first spending spree he has 0.85 M left
then he wanders into the horse track and spends 0.6 of that
so he has
0.85 M * 0.4 = 4080
M = 4080/(.4*.85)
= 12,000
100%-15%=85%
85 of60%=51%
85-51=34%
34%=4080
100%=12,000
Let's solve this problem step-by-step:
Step 1: Let's assume that the amount of money the man had at the beginning is "x".
Step 2: The man spends 15% of his money, which can be calculated as 0.15x.
Step 3: After spending 15% of his money, the man is left with x - 0.15x = 0.85x.
Step 4: The man then spends 60% of the remainder, which can be calculated as 0.6 * (0.85x).
Step 5: After spending 60% of the remainder, the man is left with 0.4 * (0.85x) = 0.34x.
Step 6: According to the problem, the remaining amount of money is 4080.
Step 7: Set up an equation: 0.34x = 4080.
Step 8: Solve the equation for x: x = 4080 / 0.34 = 12,000.
Step 9: Therefore, the man had 12,000 units of money at the beginning.
So, the man had 12,000 units of money at the beginning.
To solve this problem, we need to break it down into steps and use algebra to find the solution. Let's follow these steps:
Step 1: Let's assume the man initially had x amount of money.
Step 2: According to the problem, he spends 15% of his money. This means he has (100% - 15%) = 85% of his money remaining. In terms of x, this can be represented as 0.85x.
Step 3: Now, the man spends 60% of the remaining money. This means he has (100% - 60%) = 40% remaining. In terms of x, this can be represented as (0.40 * 0.85x) = 0.34x.
Step 4: According to the problem, the man has 4080 left after spending 60% of the remainder. So, we can write the equation:
0.34x = 4080
Step 5: To find the value of x, we can solve this equation algebraically. We can divide both sides of the equation by 0.34:
x = 4080 / 0.34
Step 6: Evaluating this expression, we have:
x = 12,000
Therefore, the man initially had 12,000 units of money.