Question

7x^12/5 - 50x^7/5 + 7x^2/5 = 0

Answer 1

I will assume you are solving

7x^12/5 - 50x^7/5 + 7x^2/5 = 0
take out common factor of x^(2/5)

x^(2/5) (7x^2 - 50x + 7) = 0
x^(2/5) (7x - 1)(x - 7) = 0

x = 0 or x = 1/7 or x = 7