# Math

Solve the system by graphing.
x+y=−2
y=13x+2

A. (6, 4); The image is of a 2-dimensional graph with an x-axis and a y-axis. One line is drawn passing through co-ordinates (-3,1) and (3,3). Another line is drawn from co-ordinate (-2,-4) to (6,4).
B. (−3, 1); The image is of a 2-dimensional graph with an x-axis and a y-axis. One line is drawn passing through co-ordinates (-3,1) and (3,3). Another line is drawn from co-ordinate (-4,2) to (2,-4). They intersect each other at (-3,1).
C. (3, 1); The image is of a 2-dimensional graph with an x-axis and a y-axis. One line is drawn passing through co-ordinates (0,2) and (3,1). Another line is drawn from co-ordinate (-2,-4) to (6,4). They intersect each other at (3,1).
D. (0, −2); The image is of a 2-dimensional graph with an x-axis and a y-axis. One line is drawn passing through co-ordinates (0,-2) and (3,-1). Another line is drawn from co-ordinate (-2,-4) to (5,3). They intersect each other at (0,-2).

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1. so, did you graph it?

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2. I don't know how to read a grapg but I graphed it. If I know the ordered pair I can use that to see if my graph is sorta correct.

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3. I don't understand the words I can understand a graph which I can clearly see. A graph in words is so confusing.

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4. You have the equations

x+y=−2
y=13x+2

You know it is a 2-D graph
The lines intersect at (-2/7,-12/7), so none of the choices listing a different intersection can be right. That leaves only (A).

Now you just have to check to see whether the lines pass through the named points.

No luck there. I suspect a typo in the equations.

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