Math

Car 1 & Car 2 leave the same location . Car 1 leaves the location 10 minutes before Car 2 and is traveling 65 mph. Car 2 is traveling at 75 mph. How long before Car 2 catches Car 1?

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  1. car 1 is 1/6 * 65 = 65/6 miles ahead when car 2 starts.

    car 2 is going 10 mi/hr faster, so it will take

    (65/6)/10 = 65/60 hr to catch up. In other words, 65 minutes.

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