chemistry

How many grams of SrCl2 is required to prepare 1 molar solution of it,

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  1. How much do you need to prepare?
    mols needed = M x L = ?
    Then mols = grams/molar mass. You know mols and molar mass, solve for grams.

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  2. grams of srcl2 over 1, hen this is the answer

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