Physics

A ski jumper glides down a 30.0 degrees slope for 80.0 ft before taking off from a negligibly short horizontal ramp. If the jumpers takeoff speed is 45.0 ft/s, what is the coefficient of kinetic friction between skis and slope?

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  1. friction force up slope = mu m g cos 30

    work done by friction = -80 mu m g cos 30

    drop in height = 80 sin 30 = 40 ft

    potential energy drop = m g (40 ft)

    ke = (1/2) m v^2

    so
    (1/2)m(45)^2 = 40 m g - 80 mu m g cos 30

    1012 = 40(32) - mu * 32 * 69.3

    1012 = 1280 - 2218 mu

    mu = (1288 - 1012)/2218 = .124

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