1. Questions

math

In a jar there are 4 red marbles 5 green marbles and 7 blue marbles.

1 what us the probability of selecting a red marble replacing it and then selecting a blue marble

2 What is the probability of selecting a red marble setting it aside and then selecting a blue marble
3 are the answers to part 1 and 2 the same why or why not
This is the only question i have on my school work if any one can plz help me that would be awesome

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please help

  1. 16 marbles

    1. independent red * blue = 4/16 * 7/16

    2. dependent red then blue = 4/16 * 7/15

    3.in number two the probability of blue is impacted by the fact that you have taken a marble out. The two draws are not independent on problem 2

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    Damon

  2. Hey guys. I so I know it seems complicated but I'll help you. You can search up this question on Brainly and you'll find my answer (username is @toulouse)
    Shorty my link is being reviewed and I'll post the link.

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    ArianaGrande_is.bae

  4. Ok so

    There are 4 red marbles.
    There are 7 blue marbles.
    There are 5 green marbles.
    There are 16 marbles in total.

    a.
    Answer = (probability of selecting a red marble)(probability of selecting a blue marble)
    First, the probability of selecting a red marble.

    Next, the probability of selecting a blue marble.

    Multiply the probabilities together.

    That is the probability for event a.

    b.
    Answer = (probability of selecting a red marble)(probability of selecting a blue marble)
    First, the probability of selecting a red marble.

    Next, the probability of selecting a blue marble WITH A RED MARBLE REMOVED.

    Multiply the probabilities together.

    That is the probability for event b.

    c.
    Obviously:

    So the answer is no.

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    >:)

  5. i was a great jeager then i got blasted by acid and exploded under the water by leatherback

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    cherno alpha

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