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Find the equation of the line that is perpendicular y=3/5x-4 that passes through the point (-1,3)
I forgot how to do this. Please help

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Anonymous

  1. Recall that perpendicular lines have slopes that are negative reciprocals of each other.

    so the slope of the given line is 3/5
    then the slope of the new line is -5/3

    new equation: y = (-5/3)x + b
    but (-1,3) lies on it, so
    3 = (-5/3)(-1) + b
    b = 3 - 5/3 = 4/3

    new line: y = (-5/3)x + 4/3

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    Reiny

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