A golfer rides in a golf cart at an average speed of 3.93 m/s for 43.3 s. She then gets out of the cart and starts walking at an average speed of 1.13 m/s. For how long (in seconds) must she walk if her average speed for the entire trip, riding and walking, is 1.99 m/s?
d1 = 3.93m/s * 43.3s = 170.2 m.
d2 = 1.13*T.
r = (d1+d2)/T = 1.99 m/s.
(170.2+1.13T)/T = 1.99.
Multiply by T:
170.2 + 1.13T = 1.99T.
1.99T - 1.13T = 170.2.
0.86T = 170.2.
T = 198 s.
Correction: r = (d1+d2)/(43.3+T) = 1.99.
(170.2+1.13T)/(43.3+T) = 1.99.
Solve for T.
To find the time the golfer must walk, we can use the concept of average speed.
Average speed is calculated by dividing the total distance traveled by the total time taken.
Let's break down the problem into parts:
1. Distance traveled in the golf cart:
The golfer rides in the golf cart at an average speed of 3.93 m/s for 43.3 s. We can find the distance by multiplying the speed and time:
Distance = Speed x Time = 3.93 m/s x 43.3 s
2. Distance traveled while walking:
We need to find the remaining distance after the golf cart ride. To do this, we subtract the distance traveled in the golf cart from the total distance.
Remaining distance = Total distance - Distance in golf cart
3. Time taken to walk:
We know that the average speed for the entire trip, including the golf cart ride and walking, is 1.99 m/s. We can use this information to find the time taken to walk:
Time = Distance / Speed
Let's now plug in the values and calculate:
Distance in golf cart = 3.93 m/s x 43.3 s
Remaining distance = Total distance - Distance in golf cart
Time taken to walk = Remaining distance / Walking speed
Total distance is not given in the question, so we can't calculate the specific time taken to walk without that information.