vs =6 volts
vth =2 volts
ida(diode current)=1m amp
no value given for resistor network
find rth(thevenien)
2,000 and 4000 do not work.
diode current must not be equal to isc.??
voc=2 volts

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  1. Diode Connected:
    Vd + (I2+Id)R1 = 6 Volts.
    0.7 + (I2+1.0)R1 = 6.
    0.7 + I2*R1 + R1 = 6.
    Eq1: I2R1 + R1 = 5.3.

    Diode disconnected:
    V2 + I2*R1 = 6 Volts.
    2 + I2R1 = 6.
    Eq2: I2R1 = 4.

    In Eq1, replace I2H1 with 4:
    4 + R1 = 5.3.
    R1 = 1.3k = 1300 Ohms.

    In Eq2, replace R1 with 1.3k:
    I2*1.3k = 4.
    I2 = 3.1 mA.
    R2 = V2/I2 = 2/3.1 = 0.65k = 650 Ohms.

    Rth = R1*R2(R1+R2)=1300*650/(1300+650)= 433 Ohms.


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