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A machine put the juice in the bottle with normal distribution with mean is equal to 50 cl, with the standard deviation 5 cl. Test was done to see if the claim is right. A sample of 100 bottles were tested. They got the average content of 48.9 cl. At ∝ =0.05, can the claim be rejected?

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iram

  1. Z = (score-mean)/SEm

    SEm = SD/√n

    Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to the Z score.

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    PsyDAG

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