Math

If you are standing near the edge of the top of a 200 feet building and throw a ball vertically upward it will be modeled by the function s(t)=-16t^2+64t+200 where s(t) is the ball's height above ground in feet and t is seconds after the ball was thrown.
A) When does the ball reach its maximum height and what is the maximum height?
T= -b/2a
T= -64/-2(-16)
T= 2 seconds
How do I find the maximum height?
B) When does the ball hit the ground? (Round to the nearest tenth of a second)
Can you please help me with this question?
C) Find s(0) and describe what it represents?
Can you please help me with this question?
D) How would I graph the quadratic function?

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  1. to find max height, plug your t = 2 into the original equation
    s(2) = -16(4) + 64(2) + 200
    = .....

    at ground, s(t) = 0
    -16t^2 + 64t + 200 = 0
    4t^2 - 16t - 50 = 0
    2t^2 - 8t - 25 = 0
    use the quadratic formula:
    t = (8 ± √264)/4
    = appr 6.062 or a negative, which we will reject

    verification:
    http://www.wolframalpha.com/input/?i=s%28t%29%3D-16t%5E2%2B64t%2B200+

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