Devils food cake has a [H+] of 2.7 x 10-8 mol/L. calculate
pH
pOH
[OH-]
To calculate the pH, pOH, and [OH-] of a solution, we can use the formula:
pH = -log[H+]
pOH = -log[OH-]
[OH-] = 10^(-pOH)
Given that the [H+] of the Devil's Food Cake is 2.7 x 10^-8 mol/L, we can calculate the pH, pOH, and [OH-] using these formulas.
1. pH calculation:
pH = -log(2.7 x 10^-8)
= -log(2.7) + log(10^-8) [Using logarithm rules]
= -log(2.7) - 8 [log(10^-8) = -8]
(Note: log here refers to the common logarithm with base 10)
You can use a calculator or a mathematical software to find the final value of pH.
2. pOH calculation:
pOH = 14 - pH [Since pH + pOH = 14 for water solutions]
(Note: For acidic solutions like Devil's Food Cake, the pH is less than 7, so pOH will be greater than 7.)
3. [OH-] calculation:
[OH-] = 10^(-pOH)
Again, you can use a calculator or a mathematical software to find the final value of pOH and [OH-].
By following these calculations, you will be able to determine the pH, pOH, and [OH-] of the given Devil's Food Cake solution.