how many grams of the solid can be formed from 206g of calcium nitrate and 140 g of phosphoric acid? answer in grams. I really need help and fast.
To find out how many grams of the solid can be formed from the given reactants, we first need to determine the balanced chemical equation for the reaction between calcium nitrate (Ca(NO3)2) and phosphoric acid (H3PO4). The balanced equation is:
3Ca(NO3)2 + 2H3PO4 → Ca3(PO4)2 + 6HNO3
From the balanced equation, we can see that 3 moles of calcium nitrate react with 2 moles of phosphoric acid to produce 1 mole of calcium phosphate.
To calculate the amount of calcium phosphate (Ca3(PO4)2) that can be formed, we need to convert the given masses of calcium nitrate and phosphoric acid into moles. For this, we will use the molecular weight of each compound.
The molecular weight of calcium nitrate (Ca(NO3)2) can be calculated as follows:
Ca = 40.08 g/mol
N = 14.01 g/mol (x 2 since there are two nitrogen atoms) = 28.02 g/mol
O = 16.00 g/mol (x 6 since there are six oxygen atoms) = 96.00 g/mol
Total molecular weight of calcium nitrate = 40.08 + 28.02 + 96.00 = 164.10 g/mol
Similarly, the molecular weight of phosphoric acid (H3PO4) is calculated as:
H = 1.01 g/mol (x 3 since there are three hydrogen atoms) = 3.03 g/mol
P = 30.97 g/mol
O = 16.00 g/mol (x 4 since there are four oxygen atoms) = 64.00 g/mol
Total molecular weight of phosphoric acid = 3.03 + 30.97 + 64.00 = 98.00 g/mol
Now we can calculate the number of moles for each compound:
Moles of calcium nitrate = mass / molecular weight = 206 g / 164.10 g/mol ≈ 1.254 mol
Moles of phosphoric acid = mass / molecular weight = 140 g / 98.00 g/mol ≈ 1.429 mol
Next, we compare the mole ratio based on the balanced equation. Since the ratio of calcium nitrate to calcium phosphate is 3:1, and we have 1.254 moles of calcium nitrate, we can expect to produce:
Moles of calcium phosphate = (1.254 mol Ca(NO3)2) * (1 mol Ca3(PO4)2 / 3 mol Ca(NO3)2) ≈ 0.418 mol Ca3(PO4)2
Finally, we can calculate the mass of calcium phosphate formed using its molecular weight:
Mass of calcium phosphate = moles of calcium phosphate * molecular weight
= 0.418 mol * (310.18 g/mol) ≈ 129.63 g
Therefore, approximately 129.63 grams of the solid calcium phosphate (Ca3(PO4)2) can be formed from the given reactants.