I wrote the balanced equation for cream of tartar and baking soda:
I identified the conjugate acid base pairs:
NaHCO3 and H2CO3, KHC4H4O6 and KNaC4H4O6
I wrote a balanced equation for carbon dioxide gas and water:
I determined the # of moles of cream of tartar needed to react with baking soda:
2.240 mol KHC4H4O6

Now I am stuck! Please help me set up this equation...

Now you want to determine the volume of the cream of tartar solution required to substitute for water based on the number of moles of cream of tartar required to react with the baking soda. You must determine the concentration of the acidic solution. Fortunately, you have a bottle of drain opener, a concentrated solution of sodium hydroxide. The bottle claims the concentration of active ingredient, the sodium hydroxide, is 3.00 M. You know this is too strong, so you dilute it 1:10 to make a 0.300 M solution of NaOH that you will use to titrate the cream of tartar.
5. Write a balanced chemical equation for this acid-base neutralization reaction:

  1. 👍
  2. 👎
  3. 👁
  1. what is the concentration of a solution made by dissolving 1.2g of salt in 3.8g of water

    1. 👍
    2. 👎

Respond to this Question

First Name

Your Response

Similar Questions

  1. chemistry

    Baking soda is sodium bicarbonate, NaHCO3, and vinegar is primarily acetic acid, HC2H3O2. When baking soda is added to vinegar, the resulting reaction produces a tremendous amount of gas, as shown in this video. Complete this


    what is the theoretical mole ratio- NaCl to NaHCO3 How do you determine the percentage error of an experimental mole ratio It would be easier for us to help you if we had the entire problem instead of just parts of it. However,

  3. chem

    Does baking soda and vinegar have a complete ionic equation? HC2H3O2 (aq) + NaHCO3 ===> NaC2H3O2(aq) + H2CO3(aq)----->H2O(l)+CO2(g)+2H2O(l)

  4. Chemistry-Repost

    Write formula equations and net ionic equations for the hydrolysis of sodium carbonate in water. Responses Chemistry - DrBob222, Friday, April 24, 2009 at 10:50pm The hydrolysis of Na2CO3 ends us as the hydrolysis of the carbonate

  1. Chemistry

    Balance this equation. NaHCO3(s) + heat ----> Na2CO3(s) + H2O(l) + CO2(g). i balanced it & got: 2NaHCO3(s)+ heat -->Na2CO3(s)+ H2O(g)+CO2(g) is this right ? Determine how many moles of CO2(g) is produced when 7mols of NaHCO3 are

  2. chemistry

    Carbon dioxide (CO2) reacts with water (H2O) to form carbonic acid (H2CO3). Which equation demonstrates the law of conservation of matter for this reaction? A. 2 CO + H2O —> H2CO3 B. CO2 + H2O —> H2CO3 C. CO2 + 2 H2O —> 2

  3. Chemistry

    Baking soda is sodium bicarbonate (NaHCO3). When you heat baking soda, it breaks down into sodium carbonate powder (Na2CO3), water vapor, and carbon dioxide. The enthalpy of this reaction is 129 kJ. Write a correct thermochemical

  4. science

    Sodium hydrogen carbonate NaHCO3, also called baking soda, is an active ingredient in some antacids used for the relief of indigestion. Determine the percent composition of sodium hydrogen carbonate.

  1. chem

    In order to neutralize the acid in 10.0 mL of 18.0 mol/L sulfuric acid that was spilled on a laboratory bench, sodium bicarbonate (baking soda) was used. The container of baking soda had a mass of 155.00g before this use, and out

  2. chemistry 12

    For the acid-base neutralization reaction of Carbonic acid, H2CO3(aq) and lithium hydroxide, LiOH(aq), write the blanced: a)complete equation b) Ionic equation c) Net ionic equation. ----------------------- i got a) H2CO3(aq) +

  3. Chemistry (mol)

    How many mol of NaHCO3 are in a 454 g box of baking soda (NaHCO3)? A. 3.81 x 10^4 mol NaHCO3 B. 1.85 x 10^–1 mol NaHCO3 C. 5.40 x 10^0 mol NaHCO3 D. 6.33 x 10^–20 mol NaHCO3 I tried doing the calculations and a came the

  4. science

    How many moles of baking soda are contributed by the 1/3 tsp. baking soda in this recipe? Assume that the density of baking soda is 1 g/ml and the molecular weight of baking soda is 84g/mol. Give your answer in moles, but without

You can view more similar questions or ask a new question.