Calculus

Find the four second partial derivatives and evaluate each at the given point.
Function
f(x, y) = x^3 + 2xy^3 − 9y
Point
(9, 2)
fxx(9, 2) =

fxy(9, 2) =

fyx(9, 2) =

fyy(9, 2) =

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  1. Fx = 3x^2 + 2y^3
    Fy = 6xy^2 - 9

    Fxx = 6x
    Fxy = 6y^2 = Fyx
    Fyy = 12x

    Now just plug in the numbers

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    2. 👎
  2. do this just like the one above
    for example
    df/dx = 3 x^2 + 2 y^3
    df/dy = 6 x y^2 - 9

    d/dx (df/dx) = 6 x
    etc

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