chemistry

1. How many grams of calcium chloride (CaCl2) are there in 600.0 mL of an aqueous solution that has a concentration of 0.450 M CaCl2?

2. The conjugate base of HS- is:

3. What mass of calcium chloride, CaCl2, is needed to prepare 3.65 L of a 1.75 M solution?
The molar mass of calcium chloride is 111.0 g/mol.

asked by angel
  1. 1. mols CaCl2 = M x L = ?
    Then grams = mols x molar mass

    2. The base is what's left after the H is gone.

    3. How many mols do you need? That's mols = M x L
    How many grams is that many mols? That's grams = mols x molar mass = ?

    posted by DrBob222
  2. mxl=270
    so the answer to 1. is 270?
    so the answer to 2. is S2-?
    so the answer to 3. is 6.3875?

    posted by anna
  3. 1. You forgot to change 600 mL to L. The answer is 0.270 mols.
    2. is yes
    3. I don't get your answer.
    M x L = 1.75 x 3.65 = ?
    ? x molar mass = ? x 111 = approx 710 grams.

    posted by DrBob222
  4. 1. is incorrect, it is not .270, i have one more chance on my practice sheet to answer this.

    2. was good, thanks

    posted by anna
  5. You misunderstood on 1.
    mols = M x L = 0.600 x 0.450 = 0.270.

    Then you omitted the second step which I wrote in my first response which is
    grams = mols x molar mass = ?
    That will be grams = 0.270 x molar mass CaCl2 = ?

    posted by DrBob222
  6. i got 29.9646 from your explaination on 1

    posted by anna
  7. is that correct?

    posted by anna

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