What volume of 18N H2SO4 is required to prepare 125 ml of 6.0 N H2SO4?
Well, I must say, you've got some strong acids on your hands! Let's get down to some clown calculations.
Now, to find the volume we need, we can use a little equation called the dilution formula. It goes like this:
C₁V₁ = C₂V₂
Where C₁ and V₁ represent the concentration and volume of the starting solution, and C₂ and V₂ represent the concentration and volume of the final solution.
We know that C₁ is 18.0 N (some real super acid stuff), V₁ is what we want to find, C₂ is 6.0 N, and V₂ is 125 ml.
Plugging those values in, we get:
18.0 N * V₁ = 6.0 N * 125 ml
Now, let's solve for V₁, the volume we need.
Dividing both sides of the equation by 18.0 N, we get:
V₁ = (6.0 N * 125 ml) / 18.0 N
Now, let's use our clown calculators for a moment...
V₁ = 41.666... (rounded to 2 decimal places)
So, to prepare 125 ml of 6.0 N H2SO4, you'll need approximately 41.67 ml of your 18.0 N H2SO4.
Remember to handle those acids with care, my friend!
To determine the volume of 18N H2SO4 required to prepare 125 ml of 6.0N H2SO4, we can use the concept of molar concentration and the dilution equation:
M1V1 = M2V2
Where:
M1 = initial concentration
V1 = initial volume
M2 = final concentration
V2 = final volume
In this case,
M1 = 18N
V1 = ?
M2 = 6.0N
V2 = 125 ml
Rearranging the equation to solve for V1:
V1 = (M2 * V2) / M1
Substituting the values:
V1 = (6.0N * 125 ml) / 18N
V1 = 41.67 ml
Therefore, approximately 41.67 ml of 18N H2SO4 is required to prepare 125 ml of 6.0N H2SO4.
To find the volume of 18N H2SO4 required to prepare 125 ml of 6.0N H2SO4, we need to use the concept of dilution.
Here's how you can calculate it:
Step 1: Use the formula for dilution:
(M1 × V1) = (M2 × V2)
Where:
M1 = Initial concentration of the solution (18N)
V1 = Initial volume of the solution (volume of 18N H2SO4 we need to find)
M2 = Final concentration of the solution (6.0N)
V2 = Final volume of the solution (125 ml)
Step 2: Plug in the values into the formula and solve for V1:
(18N × V1) = (6.0N × 125 ml)
Step 3: Rearrange the formula to solve for V1:
V1 = (6.0N × 125 ml) / 18N
Step 4: Simplify and calculate:
V1 = 500 ml
Therefore, 500 ml of 18N H2SO4 is required to prepare 125 ml of 6.0N H2SO4.
mL1 x N1 = mL2 x N2
mL1 x 18 = 125 x 6.0
Solve for mL1.