Physics

Two asteroids
of equal mass collide as shown in the
figure. After the collision, asteroid A’s
trajectory is deflected by 30 degrees
from its initial motion. Asteroid B is
initially at rest and its final velocity
makes a 45 degree angle with respect
to the initial trajectory of asteroid A.

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  1. momentum x = m Via
    momentum y = 0

    after
    m Via = m Va cos 30 + m Vb cos 45

    0 = m Va sin 30 - m Vb sin 45

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  2. a) What is the final speed of each asteroid? Express your answer as a vector.
    b) What fraction of asteroid A’s initial kinetic energy dissipates during the collision?

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  3. You have to use the two equations I derived to get Va and Vb in terms of Via, the initial speed of A
    then you can do the x and y components

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  4. The initial velocity before A hit B was 40 m/s

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  5. I still don't understand what you are trying to say.

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  6. Vb = Va sin 30/sin 45

    then
    Via = Va cos 30 + (Va sin 30/sin 45)cos 45

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  7. so Via = 40
    You did not say that
    use it

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  8. so you can solve for Va, the speed of A after
    then for Vb the speed of B after

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  9. what is Va? That is what is confusing me the most

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  10. nevermind

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  11. Va is the speed of A after collision

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  12. how would i do part b?

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  13. once you have Va and Vb
    Ke before = (1/2) m Via^2

    Ke after = (1/2) m Va^2 + (1/2) m Vb^2

    note m cancels everywhere in this problem

    I think you can do the lost over the initial

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  14. Thank you so much

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  15. You are welcome.

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