The length of a rectangle is three times its width.
If the area of the rectangle is
108 yd^2, find its perimeter.
w*3w = 108
so, w=6
p = 2(w+3w) = ?
To find the perimeter of a rectangle, we need to know the lengths of all four sides.
Let's start by assigning variables. Let's say the width of the rectangle is "w" yards. According to the problem, the length is three times the width, so we can say the length is "3w" yards.
The formula for the area of a rectangle is: Area = length * width.
Since we know the area is 108 square yards, we can write the equation as: 108 = 3w * w.
Simplifying this equation, we get: 108 = 3w^2.
Now, let's solve for w. Divide both sides of the equation by 3: 108/3 = w^2.
This simplifies to: 36 = w^2.
Taking the square root of both sides, we find: w = 6.
So, the width of the rectangle is 6 yards. Now, we can find the length by multiplying the width by 3: 3 * 6 = 18.
Therefore, the width of the rectangle is 6 yards, and the length is 18 yards.
To find the perimeter, we use the formula: Perimeter = 2 * (length + width).
Substituting the values we found, the perimeter is: Perimeter = 2 * (18 + 6).
Simplifying, we get: Perimeter = 2 * 24.
So, the perimeter of the rectangle is: Perimeter = 48 yards.