Calculus

Find the absolute maximum and absolute minimum values of f on the given interval.
f(x) = 17 + 4x − x^2, [0, 5]

I got -13 and 17, but the answers were wrong. Take the derivative for the critical values, right? To get 2 as a critical value. What from there?

asked by Callie
  1. f' = 0 = 4 - 2 x
    so x = 2, right
    at 2
    y = 17 + 8 - 4 = 21
    check end points
    at x = 0, y = 17
    at x = 5, y = 17+20 -25 =12

    21 is at the vertex and is maximum
    12 is minimum on this restricted domain

    posted by Damon

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