The school bus slows from 60km/h to 40km/h when entering the scholl zone.
a. Calculate the conversation of these speeds from km/h to m/s.
b. Given that this change of speed occured over 8 seconds, calculate the average deceleration of the bus.
My work...
a.60/3.6=17m/s
40/3.6=11.1m/s
b. i cant do b.
a. Vo = 60000m/3600s. = 16.7 m/s.
Vf = 40000m./3600s. = 11.1 m/s.
b. a = (Vf-Vo)/t = (11.1-16.7)/8 = -0.699 m/s^2.
To calculate the average deceleration of the bus, you need to use the formula:
acceleration = (final velocity - initial velocity) / time
First, let's convert the initial and final velocities from km/h to m/s:
Initial velocity = 60 km/h = 60/3.6 m/s ≈ 16.7 m/s
Final velocity = 40 km/h = 40/3.6 m/s ≈ 11.1 m/s
Next, we can substitute these values into the formula:
acceleration = (11.1 m/s - 16.7 m/s) / 8 s
Now, let's calculate the numerator:
11.1 m/s - 16.7 m/s = -5.6 m/s
Finally, divide the numerator by the time to get the average deceleration:
acceleration = -5.6 m/s / 8 s ≈ -0.7 m/s^2
Therefore, the average deceleration of the bus is approximately -0.7 m/s^2.