calculate the mass in grams of copper that will be deposited by dissolving 6.5g of zinc in copper tetraoxosulphate(vi)solution
To calculate the mass of copper that will be deposited when 6.5g of zinc is dissolved in a copper tetraoxosulphate (VI) solution, you need to use the concept of stoichiometry. Here's how you can approach this calculation:
1. Write the balanced chemical equation:
Zn + CuSO4 → ZnSO4 + Cu
This equation represents the reaction between zinc (Zn) and copper tetraoxosulphate (VI) (CuSO4) to form zinc sulphate (ZnSO4) and copper (Cu).
2. Find the molar mass of zinc (Zn) and copper (Cu):
- The molar mass of Zn is 65.38 g/mol
- The molar mass of Cu is 63.55 g/mol
3. Use the molar ratio from the balanced equation to calculate the number of moles of copper (Cu):
- From the balanced equation, we see that 1 mole of Zn reacts with 1 mole of Cu
- Therefore, the number of moles of Cu formed will be the same as the number of moles of Zn used.
4. Calculate the number of moles of Zn using its molar mass:
- Moles of Zn = Mass of Zn / Molar mass of Zn
- Moles of Zn = 6.5 g / 65.38 g/mol
- Moles of Zn = 0.0994 mol
5. Since the number of moles of Cu formed is the same as the number of moles of Zn used, the mass of copper (Cu) deposited will be the same as the mass of Zn used:
- Mass of Cu = Moles of Cu * Molar mass of Cu
- Mass of Cu = 0.0994 mol * 63.55 g/mol
- Mass of Cu = 6.31 g
Therefore, the mass of copper deposited from dissolving 6.5g of zinc in a copper tetraoxosulphate (VI) solution is approximately 6.31 grams.
To calculate the mass of copper that will be deposited by dissolving 6.5g of zinc in a copper tetraoxosulfate(VI) solution, we need to use the stoichiometry of the reaction.
The balanced chemical equation for the reaction is:
Zn(s) + CuSO4(aq) -> Cu(s) + ZnSO4(aq)
From the equation, we can see that the mole ratio of zinc to copper is 1:1. This means that for every 1 mole of zinc dissolved, 1 mole of copper will be deposited.
First, let's calculate the moles of zinc:
Molar mass of zinc (Zn) = 65.38 g/mol (you can find this in the periodic table)
Moles of zinc = Mass of zinc / Molar mass of zinc
= 6.5 g / 65.38 g/mol
= 0.0993 mol
Since the moles of zinc and copper are equal, we have 0.0993 moles of copper.
Now, let's calculate the mass of copper:
Molar mass of copper (Cu) = 63.55 g/mol (you can find this in the periodic table)
Mass of copper = Moles of copper x Molar mass of copper
= 0.0993 mol x 63.55 g/mol
= 6.30 g
Therefore, the mass of copper that will be deposited by dissolving 6.5g of zinc in a copper tetraoxosulfate(VI) solution is 6.30 grams.