Ellen has a bag with 3 red marbles and 2 blue marbles in it. She is going to randomly draw a marble from the bag 300300300 times, putting the marble back in the bag after each draw.
It is 120 because 300 times 2/5 is 120
The probability isnt just about fractions. According to my sense, it would be NOT exactly 120 times.
To determine the probability of Ellen drawing a red marble, we first need to calculate the probability of drawing a red marble on a single draw.
Ellen's bag contains 3 red marbles and 2 blue marbles, so the total number of marbles in the bag is 3 + 2 = 5.
The probability of drawing a red marble on a single draw can be calculated by dividing the number of red marbles by the total number of marbles:
P(red) = number of red marbles / total number of marbles = 3 / 5 = 0.6
Since Ellen puts the marble back in the bag after each draw, the probability remains the same for each subsequent draw.
Now, to find the probability of drawing a red marble 300300300 times in a row, we need to calculate the probability of drawing a red marble on a single draw and raise it to the power of 300300300:
P(red, 300300300 times) = P(red) ^ 300300300 = 0.6 ^ 300300300
Calculating this value would require extensive computational power and is not feasible to perform, as it would involve calculating an extremely large number. Nonetheless, the resulting probability would be very close to zero.
Thus, the probability of Ellen drawing a red marble 300300300 times in a row from the bag is virtually impossible.
Prediction: Her arm will be too tired to complete all of these draws.
Totally silly question!
Assuming she can do about 10 draws a minute, needing time to record each event,
time needed to complete your task
= 300300300/10 or 30030030 minutes
= 500500.5 hrs
= appr 20854 days
= appr 57 years
btw, was there a question in your post?