A bacteria has a doubling period of 5 days. If there are 3250 bacteria present now, how many will there be in 40 days?
I've found the growth rate to be 0.14869, but I can not find the amount of bacteria.
well, it will double 8 times in 40 days, so
3250*2^8
To determine the number of bacteria in 40 days, you can use the formula for exponential growth:
N = N₀ * (2^(t/d))
Where:
N is the final number of bacteria
N₀ is the initial number of bacteria
t is the total time elapsed
d is the doubling period of the bacteria
In this case, the initial number of bacteria N₀ is given as 3250, the total time elapsed t is 40 days, and the doubling period d is 5 days.
Plugging these values into the formula, we have:
N = 3250 * (2^(40/5))
To find the value of N, you can simplify this expression:
N = 3250 * (2^(8))
N ≈ 3250 * 256
N ≈ 832,000
Therefore, there will be approximately 832,000 bacteria in 40 days.