What is the average value of f(x) on [0,4] if the area between the graph of f (x) and the x-axis is equal to
12?
I used the average value formula and got 12.
But the answer key says 3.
My work:
M= 1/4 [12x] interval: [0,4]
48/4=12
They did not say that f(x) = 12x
They said that the area was 12. The integral was already done for you.