# maths

A sum of money is divided among three persons, X,Y and z in the ratio of 10:7:5. if Y gets \$14 more then Z, how much X will get and what is the total sum of money?

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1. x/y = 10/7
y/z = 7/5
y = z+14

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2. >10 + 7 + 5 = 22
thus there are 22 shares.
let A be the total money.
> X = (10/22)A
> Y = (7/22)A
> Z = (5/22)A
Given That:
> Y = Z + 14
> (7/22)A = (5/22)A + 14
> (7/22)A - (5/22)A = 14
> (2/22)A = 14
> A = (22/2)14
> A = 154
total amount is \$154.00
> X = (10/22)A
> X = (10/22)(154)
> X = 70
X gets \$70.00

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