The probability of selecting a banana from a bowl containing 5 bananas and 5 oranges
10 fruits
5 bananas
P(banana) = 5/10
How did you find the answer?
To find the probability of selecting a banana from a bowl containing 5 bananas and 5 oranges, you need to determine the number of favorable outcomes (selecting a banana) and the total number of possible outcomes.
Number of favorable outcomes: There are 5 bananas in the bowl.
Total number of possible outcomes: There are a total of 5 bananas and 5 oranges in the bowl, so the total number of fruits is 5 + 5 = 10.
Therefore, the probability of selecting a banana can be calculated as:
Number of favorable outcomes / Total number of possible outcomes
= 5 / 10
= 0.5
So, the probability of selecting a banana from the bowl is 0.5 or 50%.
To calculate the probability of selecting a banana from a bowl containing 5 bananas and 5 oranges, you need to know the total number of fruits in the bowl and the number of bananas.
In this case, the total number of fruits is 5 bananas + 5 oranges = 10.
The probability of selecting a banana is the number of favorable outcomes (selecting a banana) divided by the total number of possible outcomes (total number of fruits).
So the probability of selecting a banana = number of bananas / total number of fruits.
Therefore, in this case, the probability of selecting a banana = 5/10 = 1/2 = 0.5.
Hence, the probability of selecting a banana from the bowl is 0.5 or 50%.