If 3.15 mL of vinegar needs 42.5 mL of 0.115 M NaOH to reach the equivalence point in a titration, how many grams of acetic acid are in a 1.40 qt sample of this vinegar?

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  1. 0.043 liters x 0.100 M = 0.0043 moles of NaOH
    0.0043 moles of NaOH = 0.0043 moles of acetic acid
    1 quart = 32 fl oz
    1 fl oz = 29.57 mL
    1.75 quarts x 32 fl oz/qt x 29.57 mL/fl oz = 1656 mL
    0.0043 moles / 3.65 mL = 1.178x10^-3 moles/mL
    1.178x10^-3 mol/mL x 1.656x10^3 mL = 1.95 mol
    1.95 mol x 60.05 g/mol = 117 g
    117 g CH3COOH per 1.75 quarts

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