a soccer ball is kicked and given an initial velocity of 12m/s at an angle of 30 degrees from the ground what's the velocity of the ball in the x axis
To find the velocity of the ball in the x-axis, we need to consider the initial velocity and the angle of projection.
The initial velocity of the ball can be broken down into its x and y components using trigonometric functions.
Vx = V * cos(angle)
Where:
Vx is the velocity in the x-axis,
V is the initial velocity of the ball, and
angle is the angle at which the ball was kicked.
In this case, the initial velocity (V) is 12 m/s, and the angle (angle) is 30 degrees.
Plugging the values into the formula, we get:
Vx = 12 m/s * cos(30°)
Using the right triangle properties, we know that cos(30°) is equal to √3 / 2. Thus:
Vx = 12 m/s * (√3 / 2)
Now, we can simplify the equation:
Vx ≈ 12 m/s * 0.866
Vx ≈ 10.392 m/s (rounded to three decimal places)
Therefore, the velocity of the ball in the x-axis is approximately 10.392 m/s.