After leaving the runway, a plane's angle of ascent is 16° and its speed is 267 feet per second. How many minutes will it take for the airplane to climb to a height of 12,500 feet? Round answer to two decimal places.

I know the answer is 2.83, but how?

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  1. if it's air speed is 267 ft/s, then its vertical speed is

    267 sin 16° = 73.595 ft/s

    So, to gain an altitude of 12500 ft takes

    12500/73.595 = 169.848 seconds, or 2.83 minutes

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