Probability

Ten horses run in a race. How many different arrangements of placing 1st, 2nd , 3rd?
I tried by doing 10!over 7! But I don't know if that is correct , also how can you tell the finishing number as well.

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  1. 10 different horses can come in 1st
    then 9 different horses come in 2nd, and
    then 8 different horse come in 3rd

    so number of ways = 10(9)(8) = 720

    btw, 10!/7! = 10*9*8*7!/7! = 10*9*8 = 720, which was your answer, so you are right

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  2. Yes this is correct thq dear

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