# Physics

How do I calculate the upper limit and lower limits in order to obtain F(max)and F(min)for the problem below. Using the force F = (1/2)CApv^2 on the car due to air friction.
Consider a car with front cross-sectional area of A=(1.77 ± 0.02)m^2 and a drag coefficient of C = (0.38 ± -0.02) moving with a speed of v = (10.0 ± 0.5)m/s. Suppose that the density of air is p = 1.20 kg/m^3 at the sea level.

1. max use
C = .38+.02 = .40
A = 1.77+.02 = 1.79
rho = 1.20
v = 10+ .5 = 10.5

posted by Damon

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