A car enters the freeway with a speed of 6.9 m/s and accelerates uniformly for 2.7 km in 3,7 min. How fast is the car moving after this time? Answer in units of m/s.

s = 6.9(157) + 1/2 a(157^2) = 2700

Now you can find a, and then
v = 6.9+157a
= 6.9+(2(2700-6.9*157)/157^2)(157)
= 27.5 m/s