Given the equation:
6C6H12O6+O2= 6CO2+ 6H2O
How many moles of carbon dioxide will be formed upon the complete reaction of 24.1 grams of glucose with excess oxygen gas
To find the number of moles of carbon dioxide formed, you need to first find the number of moles of glucose and then use the coefficients in the balanced equation to determine the moles of carbon dioxide produced.
1. Calculate the molar mass of glucose (C6H12O6):
C6 = 6 x 12.01 g/mol = 72.06 g/mol
H12 = 12 x 1.01 g/mol = 12.12 g/mol
O6 = 6 x 16.00 g/mol = 96.00 g/mol
Molar mass of glucose = 72.06 + 12.12 + 96.00 = 180.18 g/mol
2. Convert the mass of glucose to moles:
Moles of glucose = mass of glucose / molar mass of glucose
= 24.1 g / 180.18 g/mol
3. Use the balanced equation to determine the moles of carbon dioxide produced:
6C6H12O6 + O2 → 6CO2 + 6H2O
From the equation, you can see that for every 6 moles of glucose (C6H12O6), 6 moles of carbon dioxide (CO2) are produced. Therefore, the moles of carbon dioxide are equal to the moles of glucose.
So, the moles of carbon dioxide formed = moles of glucose = 24.1 g / 180.18 g/mol
Perform the calculation to find the exact value.